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lbvjy [14]
2 years ago
6

A large box of strawberris vaires in price.the cost of a box is never graeater than or equal to 10$ the lowest price ever reache

d for the box of strawberries is 5$. write an inquality to show all the possible prices (P) for a box of strawberries
Mathematics
1 answer:
serious [3.7K]2 years ago
7 0

Answer:

10 > P ≥ 5

Step-by-step explanation:

inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions

sine the price can't be greater than or equal to 10$ we set it up 10 is greater than P ( 10 > P )

sine the lowest price ever was 5$ then we know P can't be any lower than 5$ but can still be 5$ so we set up as P is greater than or equal to 5 ( P ≥ 5 )

then to get your answer you just but the two comparisons together ( 10 > P ≥ 5 )

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"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

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Which of the following multiplication equations doesn't have the same solution as the others?
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The answer is option 2: 4b = 7. The other options all equal 4.
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