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3 years ago

<A and <B are vertical

Mathematics

1 answer:

Orlov [11]3 years ago

5 0

Answer:

Step-by-step explanation:

3x+13 = 5x+9

2x = 4

x = 2

A = 3x+13 = 19°

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3 years ago

Jane is opening a savings account with an initial deposit of $100. The bank offers a 5%

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3 years ago

Simplify <br> (-8.5) (-5) (-2).

Ber [7]

Answer:

-85

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3 years ago

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3 years ago

Describe the solutions for the quadratic equation shown below:

PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

With a = 9, b = -6 and c = 5, the roots of our equation are

$x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3} or \frac{1 - 2i}{3}$

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.

So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

Learn more about quadratic equations here:

brainly.com/question/18117039

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3 years ago