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Rainbow [258]
2 years ago
8

I need help with Algebra 2. Thank you! :)

Mathematics
1 answer:
andre [41]2 years ago
7 0

Answer:

B: 6.0

Step-by-step explanation:

-3t^2+9t+54 = 0

This is the equation that needs to be solved

Divide both sides by -3

t^2 - 3t - 18 = 0

The factors of 18 are: (1 18) (2 9) (3 6)

3 - 6 = -3 and 3 x -6 = -18

So: (t + 3) (t - 6) = 0

t = -3, 6

It can't be negative so the answer is 6

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1/8x5/6<br><br> Answers<br> 5/12<br> 3/20<br> 5/32<br> 5/48
kozerog [31]

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8 0
2 years ago
Read 2 more answers
A polyhedron with one pentagonal base is a
alekssr [168]
I think it is an apex
3 0
3 years ago
Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x - 3
k0ka [10]

Answer:

x = \frac{3}{2}

Step-by-step explanation:

Given

f(x) = \frac{x-4}{2x-3}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

Thus x = \frac{3}{2} is the vertical asymptote

5 0
3 years ago
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
At the start of the year, the balance in a married couple’s account is $ 1 , 750 . They decide to each deposit $ 35 into the acc
Dimas [21]

Answer:

f(n) = 1750 + 70n

Step-by-step explanation:

Since, each of them are depositing 35$ each month, they are adding 35x2 = 70$ each month.

So, in n months, they will be adding 70n $ to their account.

Initially, they had 1,750$ in their account. After n months, they should have 1750+70n $ in their account.

So, the function that represents this is, f(n) = 1750 +70n

7 0
2 years ago
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