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Talja [164]
2 years ago
12

Given that vector p=i+2j-2k and q=2i-j+2k, find two vectors m and m satisfying the condition;

Mathematics
1 answer:
Stels [109]2 years ago
6 0

9514 1404 393

Answer:

  • m = j +k
  • n = 2i +k

Step-by-step explanation:

There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.

Let m = 0i +1j +ak. Then we require ...

  m·p = 0 = 0×1 +1×2 +a(-2)   ⇒   0 = 2 -2a   ⇒   a = 1

m = 0i +1j +1k

__

Let n = 2i +0j +bk

  n·p = 0 = 2×1 +0×2 +b(-2)   ⇒   2 -2b = 0   ⇒   b = 1

n = 2i +0j +1k

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Problem solving with inequalities
anzhelika [568]

Option D:

15c ≤ 200

Solution:

Let c be the number of cases of tea bags.

Cost of each tea bag = 15 gold coins

Total gold coins Mad have = 200

<u>Set up an inequality:</u>

Cost of c tea bags = 15 × c = 15c

Mad can buy tea bags at most 200 gold coins.

(At most 200 means 200 is the greater value)

15 × c ≤ 200

15c ≤ 200

Hence option D is the correct answer.

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3 years ago
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The value of c is -12
8 0
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Which list of numbers is ordered from least to greatest? Please help it’s 15 points and if you can please explain or show me how
Artemon [7]

The answer is b,

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4 0
3 years ago
Read 2 more answers
Allan borrows 1870 dollars from his uncle. Two years later, he borrows another 1240 dollars. If his uncle charges him 8 percent
Anna11 [10]
For t=0
<span>Allan borrows--------------------------- > 1870 dollars

for t=6 years
</span>F1 = P*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*6=6
we have
P1=1870
r=8%
m=1
t=6 years
F1 = 1870*(1 +(0.08/1))^6------------------ >2967.45 dollars

for t=2
Allan borrows--------------------------- > 1240 dollars

for t=6 years
F2 = P2*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*4=4
we have
P2=1240
r=8%
m=1
t=4 years------------> (6-2)=4 years
F2 = 1240*(1 +(0.08/1))^4------------------ >1687 dollars

F1+F2=2967.45+1687=4654.45 dollars
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3 0
3 years ago
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timama [110]

Answer:

Binary code

Step-by-step explanation:

Code is a word or a symbol which is not disclosed to everyone and is considered as secretive. There are various codes which are required to run a software in order to minimize the risk of piracy. These codes are binary codes or java codes. These are complex so that not everyone can crack it.

3 0
3 years ago
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