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Talja [164]
3 years ago
12

Given that vector p=i+2j-2k and q=2i-j+2k, find two vectors m and m satisfying the condition;

Mathematics
1 answer:
Stels [109]3 years ago
6 0

9514 1404 393

Answer:

  • m = j +k
  • n = 2i +k

Step-by-step explanation:

There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.

Let m = 0i +1j +ak. Then we require ...

  m·p = 0 = 0×1 +1×2 +a(-2)   ⇒   0 = 2 -2a   ⇒   a = 1

m = 0i +1j +1k

__

Let n = 2i +0j +bk

  n·p = 0 = 2×1 +0×2 +b(-2)   ⇒   2 -2b = 0   ⇒   b = 1

n = 2i +0j +1k

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What are the coordinates of the point on the directed line segment from (-6, -3) to
melamori03 [73]

Given:

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.

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Section formula: If point divides a line segment in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

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3 0
3 years ago
Simplify the expression (6x^3/3x^4)^2<br> A. 12x^5/6x^6<br> B. 4/x^2<br> C. 2x^6/x^8<br> D. 2/x
Bess [88]
The Answer is B.
Sol: (6/3x^(3-4))^2
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=4/x^2


8 0
3 years ago
Read 2 more answers
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