Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
Let's say Ronnie is thinking of X.
If 2(x) = x+5, we would first distribute the 2.
2x = x+5
We would then need to isolate the variable. We would do so by getting all variables to one side. The easier choice would be to subtract x from both sides.
2x=x+5
-1x -1x
This becomes
x=5
Ronnie is thinking of the number five.
5•2=10 and 5+5=10.
Answer: there you go
Step-by-step explanation:
14 and 35 both divisible by 7
,14 and 91 both divisible by 7
14 and 38 both divisible by 3
answer is 14 and 81
Answer:
5(2x+5)
Step-by-step explanation:
This is the answer because the highest multiple is 5 for both of them.
so since it is 5 divide both numbers by 5 put 5 outside the parenthisis and
then divide the numbers inside
this will give you - 5(2x+5)
Hope it helps :)
