Answer:
Step-by-step explanation:
5/y + 7/x =24.........(1)
12/y + 2/x =24........(2)
Let 1/y = a and 1/x = b
5a + 7b = 24 ...........(3)
12a + 2b = 24...........(4)
Multiply (3) by 2 and (4) by 7
10a + 14b = 48..........(5)
84a + 14b = 168.........(6)
Substracting (5) from (6)
84a - 10a = 168 - 48
74a = 120
a = 120/74
a = 60/37
Putting a = 60/37 in (3)
5a + 7b = 24
5(60/37) + 7b = 24
300/37 + 7b = 24
Multiply each term 37
300 + 259b = 888
259b = 888 - 300
259b = 588
b = 588/259
And a = 1/y
60/37 = 1/y
Cross multiply
60y = 37
y = 37/60
Also
b = 1/x
588/259 = 1/x
Cross multiply
588x = 259
x = 259/588
<span>To make this problem simple, let's make Pat's age be 'a' for age.
So is Ron is 5 years older than double a, Ron is 2a+5 years old.
If their ages added together are less that 35 we have a + 2a + 5 < 35
Simplifying by collecting like terms, 3a +5 < 35
and subtracting 5 from each side, 3a<30
dividing each side by 3, a<10
So the greatest age Pat could be is infact 9 (as his age has to be less than 10)</span>
a: 2/38, 1/19, 5.26%
b: 6/38, 3/19, 15.79%
c: 4/38, 2/19, 10.52%
d: 0/38, 0% no chance (all black numbers are odd)
e: 3000/57,000, 3/57, 1/19 or 5.26%
<span>2√7 - (-8√7) - 3√7 = </span><span>2√7 + 8√7 - 3√7 = (2 + 8 - 3)</span><span>√7 = 7</span><span>√7</span>
Answer:
$3375 money would the student council have in four years if they invest $3000 at 5% interest compounded yearly.
Step-by-step explanation:
We are given:
Principal Amount = $3000
Interest Rate r = 5% or 0.05
n=1 (compounded yearly)
Years t= 4
We need to find future value (A)
The formula used is:
Putting values in formula and finding future value A
So, $3375 money would the student council have in four years if they invest $3000 at 5% interest compounded yearly.