A) c + t = 60
B) 3c = 7t
Multiplying A) by -3
A) -3c + -3t = -180 then adding this to b
B) 3c = 7t
180 = 10t
trucks = 18
cars = 42
Alright! So to solve these questions, you need to find out the difference. You can use ratios to solve this. For example, question #25:
A class had 30 pupils at the beginning of this school term, but now has 5 more pupils. What is the percent of increase?
The question is basically asking how much 5 is in ratio to 30. So just divide 5 (the given amount) by 30 (the total amount). The answer is 0.16, or 16%
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
0.66
Step-by-step explanation:
As division is always done before addition you would divide the 6 by 10 and then divide the 6 by 100. 6 divided by 10 is equal to 0.6 as you move the decimal point to the left once. 6 divided by 100 is equal to 0.06 as you move the decimal point to the left twice. Addition is always done after division so you would add 0.6 and 0.06 together. This will give you 0.66 as your answer.
Answer:
B
Step-by-step explanation:
distribute
5x+15-9x+4
combine like terms
-4x+19
