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stepan [7]
3 years ago
7

If an ionic compound is made of Cl- and Fe2+, the compound will be called Iron (___) chloride

Chemistry
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

iron dichloride

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A 6.0 M HCI solution is diluted to make 500 mL of a 2.5 M HCI solution. What volume of the 6.0 M HCI solution is required to mak
rodikova [14]

Answer:

V₁   = 208.3 mL

Explanation:

Given data:

Initial molarity of HCl  = 6.0 M

Final volume = 500 mL

Final molarity = 2.5 M

Volume of initial solution required = ?

Solution:

Formula:

M₁V₁   =  M₂V₂

Now we will put the values in formula.

6.0 M × V₁   = 2.5 M ×500 mL

6.0 M × V₁   = 1250 M.mL

V₁   = 1250 M.mL / 6.0 M

V₁   = 208.3 mL

4 0
3 years ago
1. Convert 67500 mg to the unit hg
Mice21 [21]

Answer:

0.675

Explanation:

4 0
4 years ago
Help ASAP I will mark brainliest for the correct answer !!!⚡️⚡️⚡️
Juliette [100K]
450 because 15x30 :)
8 0
3 years ago
Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.
Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = 2.2 \times 10^{2} ml = 220 ml

Volume of 4 glass of water = 220 \times 4 = 880 ml

We known that density of water is 1 g/ml.  Therefore, calculate the mass of water as follows.

       Mass of water = 880 ml \times 1 g/ml

                               = 880 gm

                               = 0.88 Kg               (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

            Q = mC \Delta T

\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C

Putting the given values into the above formula as follows.

         Q = mC \Delta T

             = 0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C

             = 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b).      As we know that the heat of fusion of ice is 333 J/g.

So, energy required for 8.4 \times 10^{2} g or 840 g is as follows.

          333 \times 840 = 279.72 kJ

Heat capacity of water= 4.184 J/g^{o}C

Now, heat energy will be as follows.

           Q = 4.184 \times 840 g \times 37^{o}C

               = 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

                                                  = 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ  of heat.

6 0
4 years ago
Which of the following is the main reason to use titration in chemistry
zvonat [6]
Most likely to find the equivalence point, equilibrium point, or concentration of a substance or solution!
6 0
4 years ago
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