How many joules of heat are absorbed when 73 g water are heated from 30*C to 43*C? *
2 answers:
Answer:
Explanation:
We are given the mass and change in temperature, so we must use this formula for heat energy:
The mass is 73 grams. Water's specific heat is 4.18 J/g × °C. Let's calculate the change in temperature
- ΔT= final temperature - initial temperature
- ΔT= 43 °C - 30°C
- ΔT= 13 °C
Now we know all the variables and can substitute them into the formula.
Multiply the first numbers together. The grams will cancel.
Multiply again. This time, the degrees Celsius cancel.
<u>39,668.2 Joules</u> of heat energy are absorbed.
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Answer: Le Chatleir Principle
Explanation: The answer of this question can be easily explanied through the Le Chatleir Principle which states that In order to maintain the equilibrium of the reaction, the stress applied to that particular direction will move the equilibrium to the opposite direction in which the stress has been applied.
The given reaction is -
If the amount of the oxygen is reduced to half and is being doubled, then the reaction will move in froward direction that is a rightward shift. Same situation will arise in option c and d.
If the amount of nitrogen monoxide is reduced to half or being doubled, the reaction will move towards backward direction that is a leftward reaction.
The number of hours required : 37.2 hours
<h3>Further explanation</h3>Given
⁴²K (potassium -42)
Required
The number of hours
Solution
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually, radioactive elements have an unstable atomic nucleus.
Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours
For three half-life periods :
