J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
You have the right idea that things need to get multiplied.
What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.
Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.
The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.
So we multiply the entire complex fraction by (5)(x + 6)(x -3).
Numerator: 
= (x+6)(x-3) - (5)(5)(x-3)
= (x+6)(x-3) - 25(x-3)
= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3
= (x -3)(x - 19)
Denominator:
Now we put the pieces together.
Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)
2a+3=s
I used the first letter of the name, or you can use x and y in place of a and s
Answer:
26π
Step-by-step explanation:
Hmm... This one is a little hard to understand because of the LaTeX.
Any way, way back to the question. A useful piece of information:
<u>The formula for finding the circumference of a circle is 2πr or π · d :</u>
We first need to find out what x is.
Since 2 times the radius is the diameter, we can set up our equation like this:
2(x + 6) = 3x + 5
Solving gives:
2x + 12 = 3x + 5.
We subtract 2x from both sides:
+12 = x + 5
Subtract 5:
So x = 7.
Now we can plug-and-chug:
7 + 6 = 13 times 2pi (this is the radius)
21 + 5 = 26 times pi.
<u>Check:</u>
When we check 13 (radius) times 2 should equal the diameter(26)
13 * 2 = 26.
So we are correct. The answer 26π is correct.
Answer:
-2,-2 minimum
Step-by-step explanation:
I just had a test on this
minimum because it is a minimum point it starts at the bottom
-2,-2 that is where the vertex is which is the point at the minimum
