<span>What is the axis of symmetry for f(x)=5(x+7)(x-5)? Multiply out this polynomial to obtain the equation of a parabola in the form y = ax^2 + bx + c.
f(x) = 5(x^2 - 5x + 7x -35)
Holding the coefficient 5, we have 1x^2 - 2x - 35. Here a = 1 and b = -2, and
thus x = -b / (2a) provides the x-coord. of the axis of symm. It is:
x = -(-2) / (2*1) = 1.
The axis of symmetry is the vertical line x = 1.</span>
The value of x is the number inside the parenthesis, so h(-4) gives x a value of -4.
The equation says when X is ≤ -4 use the first equation
So h(-4) = -1/2(x) -15
= -1/2(-4) -15
= 2 -15
= -13
When x = -2 (h(-2) ) use the 2nd equation:
h(-2) = 20-3x^2
=20-3(-2)^2
= 20-3(4)
=20-12
=8
Now you have -13 + 3(8)
= -13 + 24
=11
The answer should be 11