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3 years ago

Which phrases can be used to represent the inequality? Check all that apply. One-half + k greater-than 18

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

Answer:

Here we don't have the options, so i will answer in a general way.

Every sentence that has the general structure like:

"something is greater than something"

"something is smaller than something"

"Something is no greater than something"

"something is no smaller than something"

There are a lot of other sentences, for example the ones like:

"N is at least equal to M" written as: N ≥ M

"N is at most equal to M" written as: N ≤ M

And there may be other ways to represent inequalities in sentences, but this is the most general way

Then the given sentence:

"One-half + k greater than 18"

This is written as:

1/2 + k > 18

Which is an inequality.

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4 years ago

The wildflowers at a national park have been decreasing in numbers. There were 1200 wildflowers in the first year that the park

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Year New flowers

1 1200

2 300

3 75

There were 1200 wildflowers in the first year that the park started tracking them. Since then, there have been one fourth as many new flowers each year

Initially there are 1200 flowers and start decreasing by $\frac{1}{4}$

So first term is 1200 and common ratio is $\frac{1}{4}$ .

Its a geometric sequence so summation becomes

i =1∑ ∞ 1200( $\frac{1}{4})^{i-1}$

Now we find the sum

We use sum formula

$Sum = \frac{a}{1-r}$

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4 years ago

Jamie is buying 5 concert tickets, and he wants his total cost to be no more than $4 Above or below $80. Which inequality models

kumpel [21]

Answer:

Option C $\left|80-5x\right|\le 4$

Step-by-step explanation:

Let

x ----> the cost of the concert ticket

we know that

The total cost to be no more than $4 Above $80

$5x\leq 80+4$

Solve for x

$x\leq \$16.80$

The total cost to be no more than $4 below $80

$5x\geq 80-4$

Solve for x

$5x\geq 76$

$x\geq \$15.2$

therefore

The inequality that represent this problem is

$\left|5x-80\right|\le 4$

Verify

First solution (positive case)

$+(5x-80)\le 4$

$5x\le 80+4$

Solve for x

$x\leq \$16.80$ ----> is ok

Second solution (negative case)

$-(5x-80)\le 4$

Multiply by -1 both sides

$(5x-80)\ge -4$

$5x\geq 80-4$

Solve for x

$5x\geq 76$

$x\geq \$15.2$ ---> is ok

Remember that

$\left|5x-80\right|\le 4$ is equivalent to $\left|80-5x\right|\le 4$

Because is a absolute value

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