4n+78n-3/4=942
l
82n - 3/4=942
+3/4 +3/4(.75)
82n=942.75
divide 82 by both sides
n = 11.49 or 11.5
Complete Question
A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?
Answer:
The 95% confidence interval is 
No, the confidence interval includes 0.25, so the true percentage could easily equal 25%
Step-by-step explanation:
From the question we are told that
The total sample size is 
The number of offspring that is yellow peas is 
The number of offspring that is green peas is
The sample proportion for offspring that are yellow peas is mathematically evaluated as

Given the the confidence level is 95% then the level of significance is mathematically represented as


The critical value of
from the normal distribution table is

Generally the margin of error is mathematically evaluated as

=> 
=> 
The 95% confidence interval is mathematically represented as

=> 
=> 
Answer:
33
Step-by-step explanation:
Answer:
Jessica had 32 candies at the beginning.
Step-by-step explanation:
Let the number of candies Jessica had at the beginning be
.
Candies gives to Judy =
.
Now, candies left with Jessica is
.
Candies given to Reggie is
of
.
∴ Candies with Reggie is
.
Candies left with Jessica after giving to Reggie =
.
Now, Jessica lost 75% of what she had left. So, 75% of
.
∴ Candies lost = 
Now, candies left with Jessica =
.
As per question,
Candies left with Jessica at last is 4. So,


Hence, Jessica had 32 candies at the beginning.
Answer:
the answer would be B
Step-by-step explanation:
for the slope you would need to count up then over between the two points and do that until you reach where the line crosses or in this case would cross for the y-intercept