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Anit [1.1K]
3 years ago
15

X=number of hours

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
I love you :)))):))))))):)))
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Answer: ounces

Step-by-step explanation:

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(4x2 - 6x + 1) divided by (x-2)
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Answer:

x-2

Step-by-step explanation:

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Item 5
Sedbober [7]

Answer: 300.3858/ maybe 300.385

Step-by-step explanation: 4 2/7 as decimal= 4.29 x (-18) = -77.22 x -3.89=  300.3858 (3.89 = decimal form of -3 8/9)  300.3858 x 1 = 300.3858

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2 years ago
Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=
Debora [2.8K]
The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
3 0
3 years ago
The edges of a cube are 5 centimeters each and the diagonal of a face is approximately 7 centimeters. What is the approximate ar
34kurt

Answer:

C. 35sqcm

Step-by-step explanation:

area of rectangle = length × breadth

5×7=35

5 0
3 years ago
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