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3 years ago

10

Solve the equation -12 = x - 1 + 28

2 answers:

Savatey [412]3 years ago

6 0

X=15 since you subtract 1 from 27 then subtract 12 from 27 and you get 15

Goryan [66]3 years ago

5 0

Step-by-step explanation:

-28-12=x-1

-40=x-1

x=39

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When x2+3x-4 is subtracted from x (x2+3x-2) what is the difference

tankabanditka [31]

I'm assuming this is x^2 + 3x - 4 and x(x^2 + 3x - 2)

1.) First distribute x(x^2 + 3x - 2) to get x^3 + 3x^2 - 2x.

2.) Because you are subtracting all the terms from x^3 + 3x^2 - 2x, it's the same thing as distributing -1 to x^2 + 3x - 4 and then adding it to x^3 + 3x^2 - 2x.

3.) -1(x^2 + 3x - 4) = -x^2 - 3x + 4

4.) Add (x^3 + 3x^2 - 2x) + (-x^2 - 3x + 4)

5.) x^3 + 2x^2 - 5x + 4 is your final answer.

5 0

3 years ago

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What is the slope of the line

BigorU [14]

Answer:

-8/46

Step-by-step explanation:

slope is the change of y over the change in x

-5 - 3 divided by 44 - (-2)

-8/46

4 0

4 years ago

Part Two: Find they<br> 5. y= 4x + 3

skelet666 [1.2K]

Answer:

divide 4. from 4 n 3. 3 divided by 4 answer us the answer fir x and then you times that answer to 4 and that is the answer for y

7 0

3 years ago

Please helpppppppppp

Alika [10]

Answer:

x = 1/3

Step-by-step explanation:

f(x) = -3x^2 + 2x-17

This is in the form

ax^2 +bx+c

a = -3 b = 2 c = -17

The axis of symmetry is at

x = -b/2a

x = -2/ (2*-3)

x = -2/-6

x = 1/3

8 0

3 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

3 years ago

Read 2 more answers