Given the expression
-3x^4+27x^2+1200=0
let x^2=a
we can re-write our expression as:
-3a^2+27a+1200=0
-3(a^2-9a-400)=0
a^2-9a-400=0
factorizing the above we have:
a^2+16a-25a-400=0
a(a+16)-25(a+16)=0
(a+16)(a-25)
thus replacing back x^2 we have:
(x^2+16)(x^2-25)
=(x^2+16)(x-5)(x+5)
factorizing (x^2+16) we get
x^2=+/-√-16
x=+/-4i
thus the zeros of the expression are:
x=-5, x=5 , x=-4i, x=4i
Answer:
15/36
Step-by-step explanation:
Prob of getting an odd number is 3/6
Prob of getting any factor of 12 is 5/6
The keyword is AND which means time(*)
so the answer would be 3/6*5/6=15/36
Answer:
13
Step-by-step explanation:
i did the assignment
The answer is 65!
<span>How i got this was I did 6500/5 and got 1300 then i took then then multiplied by 5% and got 65
</span>I hoped I helped!
Answer:
Step-by-step explanation:
-2x + 6 = -6
-2x = -12
x = 6
