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Mazyrski [523]
3 years ago
7

A hurricane track gives the probability of a hurricane following a specific path. What type of scientific model is this?

Chemistry
1 answer:
torisob [31]3 years ago
6 0
I would say this could be called a hurricane prediction model that models what track a hurricane will follow which is most likely computer based and includes as complete a set of variables about the hurricane as possible such as wind speed and direction, location, air temperatures, date and perhaps past behaviour of similar hurricanes among many other variables.
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Inferring conclusions if you find an element in nature in its pure elemental state what can you infer about the elements chemica
Grace [21]

Answer;

-Not that reactive

The element found is not very reactive.

Explanation;

-If an element is found in nature in its pure elemental state then the the element found is not very reactive.

-There are many elements which are not much reactive. such as in metals- Ag, Au, Hg, Cu etc. and in Non metals- O2, N2, Inert gases etc.

- For checking its chemical properties you will have to examine it with O2 or C-12.


3 0
3 years ago
Can some atoms exceed the limits of the octet rule in bonding? If so, give an example.
harkovskaia [24]

Answer:

Yes. Example: <u>Sulfur hexafluoride (SF₆) molecule</u>

Explanation:

According to the octet rule, elements tend to form chemical bonds in order to have <u>8 electrons in their valence shell</u> and gain the stable s²p⁶ electronic configuration.

However, this rule is generally followed by main group elements only.

Exception: <u>SF₆ molecule</u>

In this molecule, six fluorine atoms are attached to the central sulfur atom by single covalent bonds.

<u>Each fluorine atom has 8 electrons in their valence shells</u>. Thus, it <u>follows the octet rule.</u>

Whereas, there are <u>12 electrons around the central sulfur atom</u> in the SF₆ molecule. Therefore, <u>sulfur does not follow the octet rule.</u>

<u>Therefore, the SF₆ molecule is known as a </u><u>hypervalent molecule</u><u> or expanded-valence molecule.</u>

6 0
3 years ago
A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles
RUDIKE [14]
This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

P = P1 + P2 + P3
P = (82.0575 atm.cm^3/mol.K)( 298.15 K)/1.50 x 10^3 cm^3) x (<span>0.158 mole + 0.09 mol + 0.044 mol) = 4.76 atm</span>
3 0
4 years ago
5. Calculate the mass of the following substances<br> a) 25 x 1023 molecules of N2
Anon25 [30]

Answer:

0.028kg

Explanation:

We were given 2.6 × 1023 molecules of SO 2 That means that

N = 2.6 × 1023 molecules

Use

n (number of moles) = N

                                     NA (Avogadro's constant)

to get

n =2.6×1023 molecules

   6.02 ×1023 molecules/mol  = 0.432 moles

Now use

m = n × M (molar mass)

to get

m = 0.432 mol × 64.066 g/mol = 27.677 g

So

m (in kilograms) = 27.677 g

                          103 g/kg       = 0.028 kg

7 0
3 years ago
Read 2 more answers
) Predict the product for the following reaction sequence. A) 2,2-dimethylpropanoic acid B) 3,3-dimethyl-2-butanone C) 2,2-dimet
cestrela7 [59]

Answer:

Option C. 2,2-dimethyl-1-propanol

Explanation:

The first attached picture, is the initial reactant.

Now, what happens in each step?, at first we have an alkyl bromide reacting with Mg/ether. This converts the reactant in a grignard reagent, which is often used in several ketones/ladehydes reactions, and even some acid and esthers.

Now, in the second step, we see this grignard reagent, reacting with CO₂ and H₃O⁺. At first, the grignard reagent will attach to the oxygen of the CO₂ by the MgBr, and the carbonated chain will attach to the carbonile. Then in acid medium, the OMGBr leaves the molecule, and form a carboxylic acid.

Finally, in the last step with LiAlH₄ and water, this compound just reduces the carboxylic acid to a primary alcohol, therefore, the only choice available is option c, 2,2-dimethyl-1-propanol.

See picture 2 below for the drawing.

Hope this helps

8 0
3 years ago
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