The answer is chloroplast
Answer:
c. The atoms of one element can be identical to the atoms of another element.
Explanation:
<em>Which of the following is not a statement of Dalton's atomic theory of matter?</em>
<em>a. Elements are made of atoms.</em> TRUE. An atom is the smallest particle of a chemical element that can exist.
<em>b. Atoms of a given element are identical.</em> TRUE. The only slight difference is in the mass of isotopes.
<em>c. The atoms of one element can be identical to the atoms of another element.</em> FALSE. The atoms of different elements are different from one to another.
<em>d. A given compound always has the same number and kinds of atoms. </em>TRUE. This is known as Dalton's law of constant composition.
The concentration of hydrogen ions in a solution is a measure of its acidity. So the correct option is (b) false.
When an Arrhenius acid is dissolved in water, hydrogen ions are produced:
H+(aq) + A- = HA + H2O (aq)
Here, H+ is the hydrogen cation, A- is the solvated anion, also known as the conjugate base, and HA is the non-dissociated acid. When an Arrhenius base is dissolved in water, hydroxide ions are produced:
BOH + H2O → B+(aq) + OH-(aq)
Is a material with at least one hydrogen atom that has the ability to split apart in an aqueous solution to produce an anion and an H + ion (a proton), creating an acidic solution. Bases are substances that, when dissolved in water, create hydroxide ions (OH) and a cation, resulting in a basic solution.
Learn more about hydrogen here:
brainly.com/question/16979348
#SPJ4
Answer:
50000ppm and 0.855M.
Explanation:
ppm is an unit of chemistry defined as the ratio between mg of solute (NaCl) and Liters of solution. Molarity, M, is the ratio between moles of NaCl and liters
A 5% (w/v) NaCl contains 5g of NaCl in 100mL of solution.
To solve the ppm of this solution we need to find the mg of NaCl and the L of solution:
<em>mg NaCl:</em>
5g * (1000mg / 1g) = 5000mg
<em>L Solution:</em>
100mL * (1L / 1000mL) = 0.100L
ppm:
5000mg / 0.100L = 50000ppm
To find molarity we need to obtain the moles of NaCl in 5g using its molar mass:
5g * (1mol / 58.5g) = 0.0855moles NaCl
Molarity:
0.0855mol NaCl / 0.100L = 0.855M
lanuage ? lanuage ? lanuage ?
