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dimaraw [331]
3 years ago
11

A map is drawn so that every 1 inch on the map represents 50 actual miles. The table below can be used to record the actual dist

ances between towns on the map. Actual Distances and Map Distances Actual Distance (mi.) 50 Map Distance (in.) 1 What is the actual distance between two towns that are 4 inches apart on the map? 54 miles 80 miles 150 miles 200 miles
Mathematics
2 answers:
stealth61 [152]3 years ago
8 0

Answer:

its actually D

Step-by-step explanation:

AveGali [126]3 years ago
5 0

Answer:

D

Step-by-step explanation:

i got it correct on edge (2021)

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Colt1911 [192]
1/8 + 6/8 = 7/8
17 11/13 - 9 7/13 = 8 4/13
2/8 + 4/8 = 6/8 = 3/4
8/4 + 1/4 = 9/4 = 2 1/4
9/10 + 3/10 = 12/10 = 1 1/5
2 - 3/5 = 10/5 - 3/5 = 7/5 = 1 2/5
3/4 * 4 = 12/4 = 3
1/4 * 6 = 6/4 = 1 1/2
8 0
3 years ago
Find the common difference of the arithmetic sequence. 4, 10, 16, 22, . . .
Tpy6a [65]

Answer:

6

Step-by-step explanation:

10 - 4 = 6

16 - 10 = 6

22 - 16 = 6

4 0
3 years ago
Read 2 more answers
PLZ HELP 50 POINTS AND BRAINLIEST PLZZZ HELP TIMED!!!
k0ka [10]

Answer:

i think its C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If f(x)=x^3-x+2, then (f^-1)'(2)
yawa3891 [41]

Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,

f\left(f^{-1}(x)\right) = x

\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x

which is a cubic polynomial in f^{-1}(x) with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).

Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.

f'(x) = 3x² - 1 = 0   ⇒   x = ±1/√3

So, we have three subsets over which f(x) can be considered invertible.

• (-∞, -1/√3)

• (-1/√3, 1/√3)

• (1/√3, ∞)

By the inverse function theorem,

\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}

where f(a) = b.

Solve f(x) = 2 for x :

x³ - x + 2 = 2

x³ - x = 0

x (x² - 1) = 0

x (x - 1) (x + 1) = 0

x = 0   or   x = 1   or   x = -1

Then \left(f^{-1}\right)'(2) can be one of

• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);

• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or

• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)

6 0
2 years ago
Please help :(,,,,,,???,,,,,,
nadya68 [22]

Step-by-step explanation:

The first one (f×g)(x) is asking you what is f of x times g of x. This means you multiply the function. You can multiply by the first term (5x) then the second (3) and combine like terms.

{15x}^{2} (5x) =  {75x}^{3}   \\ 19x(5x)  = 95 {x}^{2} \\  6(5x)  = 30x

{15x}^{2} (3) = 45 {x}^{2}  \\ 19x(3) = 57x \\ 6(3) = 18

Combine like terms

{75x}^{3}  +  {95x}^{2}  +  {45x}^{2}  + 30x + 57x \\  + 18 = \\   {75x}^{3}  +  {140x}^{2}  + 87x + 18

The second one asks you to divide.

Factor out f(x):

{15x}^{2}  + 19x + 6

From dividing f(x) /g(x)

\frac{ {15x}^{2} + 19x + 6 }{5x + 3}

To

\frac{(5x + 3)(3x + 2)}{5x + 3}

Cancel like terms since (5x+3) is on top and bottom of fraction.

You get 3x+2

5 0
4 years ago
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