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salantis [7]
3 years ago
7

I need help with this math question. Please help!

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer:

A) 19,30

Step-by-step explanation:

Add the x-values to 2(4)=8

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27 and 36 have a Greatest Common Factor of 9 so...
27/36 = 3/4 
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Find the slope and standard form of the line that passes through the points (3, 6) and (4, 5).
qwelly [4]

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Step-by-step explanation:

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3 years ago
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Ainat [17]

The point which doesn't lie on the curve y = x² is

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4 0
3 years ago
Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the
galina1969 [7]

Answer:

a. The margin of error is 2.29.

b. 19.23 to 23.81

Step-by-step explanation:

The sample size is n=64.

We start by calculating the sample mean and standard deviation with the following formulas:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}

The sample mean is M=21.52.

The sample standard deviation is s=6.89.

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{6.89}{\sqrt{64}}=\dfrac{6.89}{8}=0.861

The degrees of freedom for this sample size are:

df=n-1=64-1=63

The t-value for a 99% confidence interval and 63 degrees of freedom is t=2.656.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.656 \cdot 0.861=2.29

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 21.52-2.29=19.23\\\\UL=M+t \cdot s_M = 21.52+2.29=23.81

The 99% confidence interval for the mean is (19.23, 23.81).

5 0
3 years ago
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