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Answer:
From the given data, there is not enough evidence to prove that there is a statistically significant difference between the two population means
Step-by-step explanation:
The number of younger moms, in the study = 837
The average weight gain of younger moms, ₁ = 30.67 pounds
The standard deviation of the weight gain of younger moms, s₁ = 14.69 pounds
(30.67 - 28.52)/√((14.69^2)/837 + 13²/143))
The number of younger moms, in the study = 143
The average weight gain of mature moms, ₂ = 28.52 pounds
The standard deviation of the weight gain of mature moms, s₂ = 13 pounds
The test statistic for the difference in two populations is given as follows;
Therefore, we get;
The test statistic ≈ (1.7919)
Using a graphing calculator, we get;
The critical-t = ±1.971379, p = 0.07459697
Therefore, given that the test statistic, (1.7919), < critical-t (0.07459697), we fail to reject the null hypothesis, therefor, the given data does not provide convincing evidence that there is a significant difference between the two population means