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Pavlova-9 [17]
2 years ago
15

I need help please....

Mathematics
2 answers:
rjkz [21]2 years ago
8 0
It would be be x= -7
Semmy [17]2 years ago
5 0

Answer:x=-7

Step-by-step explanation:

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15 + 4x = 12 + x nm jjk kj k j jk kj k kj kjkj
Marta_Voda [28]

Answer:

x = −1

Step-by-step explanation:

3 0
3 years ago
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Jamie bought 5/8 of wheat flour. He also bought 1/4 pound of white flour. How much flour did he buy
KonstantinChe [14]
7/8     you have to make 1/4 into 2/8  and 2/8+5/8=7/8







7 0
4 years ago
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The least common multiple of two numbers is 60 and one of the numbers is 7 less than the other number.What are the numbers.Justi
denis-greek [22]

Answer:

As the least common multiple of two numbers is 60 , the two numbers are factors of 60 . Among {1,2,3,4,5,6,10,12,15,20,30,60} , 3 & 10 and 5 & 12 are the only two pair of numbers whose difference is 7 . But Least common multiple of 3 and 10 is 30

6 0
3 years ago
In parallelogram RSWY, find m
LuckyWell [14K]

Answer:

Part A) m\angle R=110^o

Part B) m\angle S=70^o

Step-by-step explanation:

we know that

In a parallelogram, opposite angles are congruent and consecutive angles are supplementary

step 1

Find the value of x

we know that

m\angle R=m\angle W ----> by definition of parallelogram (opposite angles are congruent)

substitute the given values

(5x-90)^o=(2x+30)^o

solve for x

5x-2x=30+90\\3x=120\\x=40^o

step 2

Find the measure of angle R

m\angle R=(5x-90)^o

substitute the value of x

m\angle R=(5(40)-90)=110^o

step 3

Find the measure of angle S

we know that

m\angle R+m\angle S=180^o ---> by definition of parallelogram (consecutive angles are supplementary)

we have

m\angle R=110^o

substitute

110^o+m\angle S=180^o

m\angle S=180^o-110^o

m\angle S=70^o

8 0
3 years ago
Lynn is trying to determine how far away Student B is from the balloon. He decides to use the
kaheart [24]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the image that illustrates the scenario is not given.</em>

<em>However, I can deduce that the question is about a right-angled triangle.</em>

<em>So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.</em>

<em />

<u>For triangle A (solve for b)</u>

Using cosine formula.

\cos \theta = \frac{Adjacent}{Hypotenuse}

\cos 60= \frac{5}{b}

Make b the subject

b= \frac{5}{\cos 60}

<u>For triangle B (solve for b)</u>

Using cosine formula.

\sin \theta = \frac{Opposite}{Hypotenuse}

\sin 60= \frac{b}{5}

Make b the subject

b = 5\sin 60

<u>For triangle C (solve for b)</u>

Using cosine formula.

\tan \theta = \frac{Opposite}{Adjacent}

\tan 60= \frac{b}{5}

Make b the subject

b = 5\tan 60

3 0
3 years ago
Read 2 more answers
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