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snow_lady [41]
2 years ago
9

Can someone please help complete this, it’s due at midnight and I don’t understand at all.

Mathematics
1 answer:
Bezzdna [24]2 years ago
5 0

Answer:

You just read it

Step-by-step explanation:

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F(x) =- (3x +9) – 13 find f(-5)
belka [17]

f(x) = -(3x + 9) - 13\\f(-5) = -(3 \cdot (-5) + 9) - 13\\= -(-15 + 9) - 13\\= -(-6) - 13\\= 6 - 13\\= - 7

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3 years ago
The acceleration of segment D is____ m/s2.
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Step-by-step explanation:

4 0
2 years ago
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How much would you need to deposit in an account now in order to have $4000 in the account in 10 years? Assume the account earns
gogolik [260]

Answer:

  $2355.06

Step-by-step explanation:

Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.

  A = P(1 +r/n)^(nt)

where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.

Filling in the given values, we have ...

  4000 = P(1 +.053/52)^(52·10) = P(1.6984738)

  P = 4000/1.6984738 ≈ 2355.06

You would need to deposit $2355.06 in order to have $4000 in 10 years.

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3 years ago
Find the gradient of line ab
ziro4ka [17]
Please give more clear explanation for this question so I can help you.
4 0
2 years ago
Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)
borishaifa [10]

Answer:

Since,

\frac{d}{dx}x^n = nx^{n-1}

\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))

\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}

1) y = 8x e^x

Differentiating with respect to x,

\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)

2) y = 5x e^{x^4}

Differentiating w. r. t x,

\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)

3) y = x^8 + \frac{5}{x^4}

Differentiating w. r. t. x,

\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}

4) f(t) = te^{11}-6t^5

Differentiating w. r. t. t,

f'(t) = e^{11} - 30t^4

5) g(p) = p\ln(2p+3)

Differentiating w. r. t. p,

g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)

6) z = (te^{6t}+e^{5t})^7

Differentiating w. r. t. t,

\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})

7) w =\frac{2y + y^2}{7+y}

Differentiating w. r. t. y,

\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}

7 0
3 years ago
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