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3 years ago

Five increased by the product of a number and 9 is greater than -27 As an inequality

Mathematics

1 answer:

Brut [27]3 years ago

3 0

Answer:

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Please help! Really easy math, need it asap!!! It's in the picture

Dominik [7]

Answer:

answers are: (-1,-2), (1,2), (-1,5), (1,-5). in other words, option 2, 6, 7, and 8.

Step-by-step explanation:

hope it helps

3 0

2 years ago

I'm confused. Help. Find x please.

miss Akunina [59]

Answer:

x = 2 and x = 10

Step-by-step explanation:

(x+3)^2 = (x - 5)^2 + (x + 2)^2

x^2 + 6x + 9 = x^2 - 10x + 25 + x^2 + 4x + 4

x^2 + 6x + 9 =2x^2 - 6x + 29

x^2 - 12x + 20 = 0

(x - 10)(x - 2) = 0

x - 10 = 0; x = 10

x - 2 = 0; x = 2

4 0

2 years ago

Me please I don’t understand

irakobra [83]

9 + 4 = 13

She is 13 floors away

8 0

2 years ago

Read 2 more answers

the population of arizona is estimated go increase by 6.2% every year. if the population was 4.18 million in 2016 estimate popul

aleksklad [387]

Given:

a.) The population of Arizona is estimated to increase by 6.2% every year.

b.) The population was 4.18 million in 2016.

For us to be able to determine the population in 2022, we will be using the following formula:

$\text{ P = P}_0e^{rt}$

Where,

P = Total population after time (t)

P₀ = Starting population = 4.18 million

r = Growth rate (in decimal form) = 6.2%/100 = 0.062

t = time (in years) = 2022 - 2016 = 6 years

e = Euler's number = 2.71828182845

We get,

$\text{ P = P}_0e^{rt}\text{ = (4,180,000)(}2.71828182845)^{0.062(6)}$ $\text{ P = 6,063,645.861797897 }\approx\text{ 6,063,646}$

Therefore, the population in 2022 will be approximately 6,063,646.

7 0

11 months ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

3 years ago