Domain is all real, yep
vertex of y values is from2 to infinity, so 2nd is false
y int is where x=0, that is at y=2, nope so 3rd is false
2 up and 1 to left, so no for 4th
x intercept? there are none
answer is only first option
Answer:
a < 16
Step-by-step explanation:
We must get a alone to solve this. So first multiply by 2
3a/2 < 24
*2
3a < 48
Divide by 3
a < 16
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
I would probably distribute 15 with the parentheses 15x 9860 which is 147,900 then you would add 6997+147,900
Y= 154187
Answer:
Radius = 21
Step-by-step explanation:
Volume of a sphere = 4/3 * pie * radius^3
12,348 pie = 4/3 * pie * radius ^3
12,348 = 4/3 * radius^3
(12,348 * 3)/ 4 = radius^3
9261 = radius^3
radius = ![\sqrt[3]{9261}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9261%7D)
radius = 21