Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
Answer: -4
Step-by-step explanation:
2.5x = -10
1. divide -10 by 2.5
2. x = -4
Answer:
r = 1/3
= 1
Step-by-step explanation:
1 + 1/3 + 1/9 + 1/27 + 1/ 81
In this series a is the first term = 1
r is the common ratio = 2nd term/1st term = 3rd term/ 2nd term
r = 1/3 ÷ 1 = 1/9 ÷ 1/3
r = 1/3
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Answer:
36 feet.
Step-by-step explanation:
We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is 
. We are asked to find the maximum height of the ball.
We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.
To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.
Let us find x-coordinate of parabola using formula 
.
So, the x-coordinate of the parabola is 
. Now, we will substitute in our given equation to find y-coordinate of parabola.
Therefore, the maximum height of the ball is 36 feet.
