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Answer:
The phase difference between yA and yB is
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t - ) And
yB = 8 sin(2t - )
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( - +
)
Or, phase difference between yA and yB =
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is Answer
<h3>Therefore they are perpendicular.</h3>
Step-by-step explanation:
A equation of line is
y =mx +c
Here the slope of the line is m.
Given equations are
x - 2y = 18
⇔-2y = -x +18
............(1)
and 2x + y = 6
⇔y = -2x +6 ............(2)
Therefore the slope of equation (1) is=
Therefore the slope of equation (2) is= -2
If two lines are perpendicular, when we multiply their slope we get -1.
therefore,
=
. (-2) = -1
Therefore they are perpendicular.
