Hello from MrBillDoesMath!
Answer:
Choice C [16,100]
Discussion:
Let "x" be the score needed on the 5th exam to achieve an average score >= 60. Then
(50 + 90 + 66 + 78 + x)/5 >= 60 => (multiply both sides by 5)
(50 + 90 +66 + 78) + x >= 60*5 = 300 =>
(284) + x >= 300 =>
x >= 300 - 284 = 16.
As x is a percent, x <= 100, so the interval is [16, 100], which is Choice C.
Thank you,
MrB
4 times the sum of the least and greatest integers ⇒ 4(n + n +2) = 4n + 8
12 less than three times the least integer ⇒ 3n - 12
4n + 8 = 3n - 12
4n - 3n + 8 = 3n - 3n - 12
n + 8 - 8 = -12 - 8
n = -20
-20, -19, -18 are the integers and the least is -20
Answer:
-8r + 6
Step-by-step explanation:
-4r - (4r - 6) [original equation]
-4r - 4r + 6 [distribute the "-"]
-8r + 6 [combine like terms]
X-5 is your answer. hope that helps
