Each pound costs $3.35. Hope this helped
Answer:
1/3
Step-by-step explanation:
Simplify the following:
1 - 2/3
Put 1 - 2/3 over the common denominator 3. 1 - 2/3 = 3/3 - 2/3:
3/3 - 2/3
3/3 - 2/3 = (3 - 2)/3:
(3 - 2)/3
3 - 2 = 1:
Answer: 1/3
The bottom answer is correct. I had some trouble with this so I had to find x and y in separate parts.
TO FIND X
notice that the top triangle and bottom triangles are similar, meaning if you multiple all three sides of one by a specific number, it becomes the same size as the bottom triangle.
17 x n = 8, therefore n=8/17
8 x n = X, therefore X=64/17
For some reason, this does not give a correct value for Y, so I had to use trig
TO FIND Y
Notice that the angle DAB is the same as DBC (lets call this angle Ø)
Using trig rule, we know that the cos of an angle is equal to the adjacent side divided by the hypotenuses.
We can now form some equations:
cosØ = 15/17 (from the top triangle)
cosØ = 8/Y (from bottom triangle)
Now we know that Y=(8x17)/15 = 136/15
X=64/15 Y=136/15
You will have to type it into Microsoft word first, type a number or algebraic expression into a Word document. Press the "Ctrl," "Shift" and "=" keys on your keyboard to turn on the Superscript mode. Enter another number or expression signifying the exponent.
Hope this helps! :)
The graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
-3x + 5y = -15
The above function shows a linear function we can write it as:
5y = 3x - 15
y = (3x - 15)/5
If x = 0, y = -3
x = 1, y = -2.4
x = 2, y = -1.8
x = -1, y = -3.6
x = -2, y = -4.2
Thus, the graph of the function -3x+5y=-15 is a linear function we can draw it by finding the values of y for every value of x.
Learn more about the function here:
brainly.com/question/5245372
#SPJ1
