D = sqrt(3s^2) where s is the length of the side. Solving for s,
<span>3s^2 = d^2 iff </span>
<span>s^2 = d^2 / 3 iff </span>
<span>s = sqrt(d^2 / 3) </span>
<span>= d / sqrt(3) or d sqrt(3) / 3 </span>
<span>Surface area of the cube = 6 s^2. Thus, </span>
<span>A = 6 (d / sqrt(3))^2 </span>
<span>= 6d^2 / 3 </span>
<span>= 2d^2 </span>
<span>Volume = s^3. Thus, </span>
<span>V = (d / sqrt(3))^3 </span>
<span>= d^3 / 3sqrt(3) </span>
<span>= d^3 sqrt(3) / 9</span>
To determine the unit rate of pages, that is, the number of pages Leo reads in one hour you can use cross multiplication
1/3h _____14 pages
1h______x pages

Leo reads 42pages/hour
Answer:
Answer would be x=1.
Step-by-step explanation:
Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.
To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.
A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

Similarly, but exchanging the role of x and y, we compute the length of BC:

So, the area of the rectangle is 
The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:


So, the area of the portion located in the third quadrant is 
This means that the ratio between the two area is

If we want this ratio to be a percentage, just make sure that the denominator is 100:
