Answer:
Step-by-step explanation:
![36-\left[100\div \:560-32\left(8\div \:4-1\right)\right]\\\\100\div \:560-32\left(8\div \:4-1\right)\\\\=100\div \:560-32\cdot \:1\\\\=\frac{100}{560}-32\cdot \:1\\\\=\frac{100}{560}-32\\\\=-\frac{891}{28}\\\\\\=36-\left(-\frac{891}{28}\right)\\\\36-\left(-\frac{891}{28}\right)\\\\=36+\frac{891}{28}\\\\\frac{36\cdot \:28}{28}+\frac{891}{28}\\\\\frac{36\cdot \:28+891}{28}\\\\=\frac{1899}{28}\\\\\\\frac{1899}{28}(1899\div28)=67\frac{23}{28}](https://tex.z-dn.net/?f=36-%5Cleft%5B100%5Cdiv%20%5C%3A560-32%5Cleft%288%5Cdiv%20%5C%3A4-1%5Cright%29%5Cright%5D%5C%5C%5C%5C100%5Cdiv%20%5C%3A560-32%5Cleft%288%5Cdiv%20%5C%3A4-1%5Cright%29%5C%5C%5C%5C%3D100%5Cdiv%20%5C%3A560-32%5Ccdot%20%5C%3A1%5C%5C%5C%5C%3D%5Cfrac%7B100%7D%7B560%7D-32%5Ccdot%20%5C%3A1%5C%5C%5C%5C%3D%5Cfrac%7B100%7D%7B560%7D-32%5C%5C%5C%5C%3D-%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5C%5C%3D36-%5Cleft%28-%5Cfrac%7B891%7D%7B28%7D%5Cright%29%5C%5C%5C%5C36-%5Cleft%28-%5Cfrac%7B891%7D%7B28%7D%5Cright%29%5C%5C%5C%5C%3D36%2B%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B36%5Ccdot%20%5C%3A28%7D%7B28%7D%2B%5Cfrac%7B891%7D%7B28%7D%5C%5C%5C%5C%5Cfrac%7B36%5Ccdot%20%5C%3A28%2B891%7D%7B28%7D%5C%5C%5C%5C%3D%5Cfrac%7B1899%7D%7B28%7D%5C%5C%5C%5C%5C%5C%5Cfrac%7B1899%7D%7B28%7D%281899%5Cdiv28%29%3D67%5Cfrac%7B23%7D%7B28%7D)
Divide both length and width by the dialtion factor and that will be the dimensions of the new rectangle. 2.5714in by 3.4286in. Round as needed
Let’s start with putting the unknown to x, in this case it is the number.
5x-5=7+3x, so now we just solve this equation.
5x-3x=7+5
2x=12
x=6
the number is 6
The answer to your problem is 37.
