Write the equation of the line that is parallel to y=3x-3 and passes through the point (-1,1)
2 answers:
The given equation of line is
Which is of the form
Where m is the slope which is 3 here.
And slope of parallel lines are equal. So slope of the required line is 3 too .
Now we use slope intercept form, and plug the values of the slope and the given point and solve for b, that is
So we have m =3 and b=4. Therefore required equation of line is
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E
e=mfg
Where m is a constant of proportionality;
e=4, f=2 and g=8
Then;
4=m*2*8
4=16m
m=0.25
e=mfg
Where m is a constant of proportionality;
e=4, f=2 and g=8
Then;
4=m*2*8
4=16m
m=0.25
Answer:
Given: Segment AB || segment DE, C is the midpoint of segment DB.
Prove: ΔA CB ≅ ΔE CD
Proof: In ΔA CB and ΔE CD
C is the Mid point of B D.
BC=C D→ definition of midpoint
∠A CB= ∠ EC D→→vertical angles are congruent
∠BAC=∠DEC→→[AB║DE,so alternate angles are equal]
→→ΔA CB ≅ ΔE CD[A AS or A SA]
Option B: vertical angles are congruent
