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torisob [31]
2 years ago
10

Write the equation of the line that is parallel to y=3x-3 and passes through the point (-1,1)

Mathematics
2 answers:
Nikolay [14]2 years ago
7 0

The given equation of line is

y=3x-3

Which is of the form

y = mx +b

Where m is the slope which is 3 here.

And slope of parallel lines are equal. So slope of the required line is 3 too .

Now we use slope intercept form, and plug the values of the slope and the given point and solve for b, that is

1=3(-1)+b \\ 1 = -3+b \\ 1+3 = b \\ b=4

So we have m =3 and b=4. Therefore required equation of line is

y = 3x+4

OverLord2011 [107]2 years ago
4 0
Y= -3x+4 (The answer should be this equation, im very certain of it) 
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sergeinik [125]

Answer:

140

Step-by-step explanation:

A regular polygon is a shape with equal sides and angles. Because of this, we can write the following equation to set two sides equal to each other:

3a+b+3=2a+2b+6

Solving, we will get a in terms of b:

3a=2a+b+3,\\a=b+3

Now we can substitute a for (b+3) into our equation:

5a-2b+1=2a+2b+6,\\5(b+3)-2b+1=2(b+3)+2b+6,\\3b+16=4b+12,\\-b=-4,\\b=\boxed{4}

Therefore, the length of each side of this polygon is 5(4+3)-2(4)+1=28.

Since the perimeter of the polygon consists of all five sides, the perimeter is:

p=28\cdot 5 =\boxed{140}

6 0
3 years ago
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How can you tell whether the parabola had a vertical or horizontal shift?
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