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torisob [31]
3 years ago
10

Write the equation of the line that is parallel to y=3x-3 and passes through the point (-1,1)

Mathematics
2 answers:
Nikolay [14]3 years ago
7 0

The given equation of line is

y=3x-3

Which is of the form

y = mx +b

Where m is the slope which is 3 here.

And slope of parallel lines are equal. So slope of the required line is 3 too .

Now we use slope intercept form, and plug the values of the slope and the given point and solve for b, that is

1=3(-1)+b \\ 1 = -3+b \\ 1+3 = b \\ b=4

So we have m =3 and b=4. Therefore required equation of line is

y = 3x+4

OverLord2011 [107]3 years ago
4 0
Y= -3x+4 (The answer should be this equation, im very certain of it) 
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Let's use the line on the right side. In the smaller triangle, the length is 4. The same side on the bigger triangle is 12. The ratio of the smaller triangle to the bigger triangle is:

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Look at the picture.

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