Question

Write the equation of the line that is parallel to y=3x-3 and passes through the point (-1,1)

Answer 1

The given equation of line is

$y=3x-3$

Which is of the form

$y = mx +b$

Where m is the slope which is 3 here.

And slope of parallel lines are equal. So slope of the required line is 3 too .

Now we use slope intercept form, and plug the values of the slope and the given point and solve for b, that is

$1=3(-1)+b \\ 1 = -3+b \\ 1+3 = b \\ b=4$

So we have m =3 and b=4. Therefore required equation of line is

$y = 3x+4$

Answer 2

Y= -3x+4 (The answer should be this equation, im very certain of it)