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Reptile [31]
3 years ago
7

A town's population is 33,600. About 125 people move out of the town each month. Each month, 150 people on average move into tow

n. A nearby town has a population of 35,000. It has no one moving in and an average of 150 people moving away every month. In about how many months will the populations of the towns be equal? Write an equation to model the situation. Then solve the equation and answer the question Which equation models the situation? OA. 150m + 125m + 35,000 = 33,600 + 150m OB. 150m - 125m + 35,000 = 33,600 - 150m O C. 150m - 125m +33,600 = 35,000 - 150m OD. 150m + 125m +33,600 = 35,000 + 150m​
Mathematics
2 answers:
klio [65]3 years ago
3 0

Answer:

I believe it to be C

Step-by-step explanation:

lesya692 [45]3 years ago
3 0

Answer:

The answer came up as D actually.

Step-by-step explanation:

N/A

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The table shows the number of books donated to a library each month. Suppose the growth continues exponentially.
telo118 [61]
\bf \begin{array}{ccll}
\stackrel{t}{months}&\stackrel{A}{books}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
0&80\\
1&100\\
2&125
\end{array},    we know that on Month 0, the Books were 80

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &80\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &0\\
\end{cases}
\\\\\\
80=I(1+r)^0\implies 80=I\qquad therefore\qquad \boxed{A=80(1+r)^t}

we also know that on the first month there were 100 books,

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &100\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &1\\
\end{cases}
\\\\\\
100=80(1+r)^1\implies \cfrac{100}{80}=1+r\implies \cfrac{5}{4}=1+r
\implies 
\cfrac{5}{4}-1=r
\\\\\\
 \cfrac{1}{4}=r\implies 0.25=r\qquad therefore\qquad \boxed{A=80(1+0.25)^t}

now, how many books when t = 8?   A=80(1+0.25)⁸, or A=80(1.25)⁸.
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