FOIL I need help please

A scientist has two solutions, which she has labeled Solutuion A and Solution B. Each contains salt. She knows that Solutuion A

ratelena [41]

a = amount (in oz) of solution A

b = amount of solution B

The scientist wants a mixture of 110 oz, so

a + b = 110

Solution A consists of 65% salt, so each ounce of solution A contributes 0.65 oz of salt; similarly, each ounce of B contributes 0.9 oz. The mixture is supposed to consist of 75% salt, which amounts to 0.75 * (110 oz) = 82.5 oz of salt. So

0.65 a + 0.9 b = 82.5

Solve for a and b:

b = 110 - a

0.65 a + 0.9 (110 - a) = 82.5

0.65 a + 99 - 0.9 a = 82.5

0.25 a = 16.5

a = 66 ==> b = 44

5 0

3 years ago

Which is an advantage of using equations for solving problems?

Arisa [49]

Answer:

D.Every problem needs an equation in order to be able to solve it

4 0

3 years ago

Read 2 more answers

What is the area of the triangle shown below?

Nimfa-mama [501]

Answer:

300 mm squared

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A box of 42 chocolates contains milk and dark chocolates in the ratio of 3:4. How many chocolates of each type there are?

Elza [17]

<h2>Answer:The number of milk chocolates are 18 and the number of dark chocolates are 24.</h2>

Step-by-step explanation:

Let the number of milk chocolates be $m$ .

Let the number of dark chocolates be $d$ .

Given that the box contains the milk and dark chocolates in the ratio $3:4$ .

So, $\frac{m}{d}=\frac{3}{4}$ ...(i)

Given that the total number of chocolates are $42$ .

So, $m+d=42$ . ...(ii)

Using (i) and (ii),

$m+\frac{4}{3}m=42$

$\frac{7}{3}m=42$

$m=18$

$d=\frac{4}{3}m=\frac{4}{3}\times 18=24$

So,the number of milk chocolates are $18$ and the number of dark chocolates are $24$ .

4 0

3 years ago

Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams

Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0

3 years ago