That would be in the II quadrant
So across to negative 6 and up to 7 is your coordinate
Answer:
2x² - 6x
Step-by-step explanation:
(3x² - 4x + 8) + (- x² - 2x - 8) ← remove both parenthesis
= 3x² - 4x + 8 - x² - 2x - 8 ← collect like terms
= 2x² - 6x
Answer:
D and E
UV and SV
∠U and ∠S
Step-by-step explanation:
yes
5-3 is 2 multiply that by 3 and you get 6 add that to 53 and you get 59... using PEMDAS