Let a₁ , a₂ , a₃ , a₄ ,... .be a given sequence.
The common ratio of this sequence is the following:
a₂/a₁ = a₃/a₂ = a₄/a₃ = r
Example: 5, 25, 125, 625, ...The common ration is:
25/5 = 125/25 = 625/125 = 5. So r=5 is the common ratio
Answer:
The solution of the given trigonometric equation

Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given






<u><em>Step(ii)</em></u>:-
The solution of the given trigonometric equation

<u><em>verification </em></u>:-

put 


Both are equal
∴The solution of the given trigonometric equation

Answer:
a
Step-by-step explanation:
Writing this problem in symbols instead of in words greatly simplifies it:
(2 2/3) * (1 1/5) * (1 1/2)
Write each quantity (inside each set of parentheses) as an improper fraction:
(8/3) * (6/5) * (3/2)
Now multiply the numerators thru: 8*6*3 / 3*5*2
Notice that we can reduce this by dividing the 8 by the 2 and dividing the 6 by the 3: 4*3*3 36
---------- = -----------
5 5
<span>304.688. Take 25% of 406.25, which is 101.562 and then subtract it from 406.25.</span>