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DerKrebs [107]
3 years ago
5

Write an equation of the line that passes through (1, −1) and is perpendicular to the line y=1/2x−3. An equation of the perpendi

cular line is y=
Mathematics
2 answers:
ANEK [815]3 years ago
8 0
We know that a line is perpendicular to another line if one slope is the opposite reciprocal  of the other. So, the slope of the line perpendicular to y=1/2x-3 would by -2/1 or -2. Now, to find the y intercept, plug in the coordinate (1, -1) to the equation y = -2x + b. 

-1 = -2(1) + b
 
-1 = -2 + b

1 = b

Now we know the y intercept and slope of the new line, which is enough to make the equation. y = -2x + 1 is your answer. 

Hope this helps!! :)

lapo4ka [179]3 years ago
6 0
Y = 1/2x - 3. Slope here is 1/2. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So the perpendicular line will have a slope of -2.

y = mx + b
slope(m) = -2
(1,-1)...x = 1 and y = -1
now we sub and find b, the y int
-1 = -2(1) + b
-1 = -2 + b
-1 + 2 = b
1 = b

so ur perpendicular equation is : y = -2x + 1
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Find the value of x in each figure
Angelina_Jolie [31]

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20...90°-46°

=44°

therefore 44÷4

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therefore x=11

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6 0
2 years ago
What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in
elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

<em><u>Solution:</u></em>

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>

A = \frac{1}{2} a \sqrt{c^2 - a^2}

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}

A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727

Thus area of triangle is 12.727 square inches

5 0
3 years ago
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