We know that a line is perpendicular to another line if one slope is the opposite reciprocal of the other. So, the slope of the line perpendicular to y=1/2x-3 would by -2/1 or -2. Now, to find the y intercept, plug in the coordinate (1, -1) to the equation y = -2x + b.
-1 = -2(1) + b
-1 = -2 + b
1 = b
Now we know the y intercept and slope of the new line, which is enough to make the equation. y = -2x + 1 is your answer.
Y = 1/2x - 3. Slope here is 1/2. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So the perpendicular line will have a slope of -2.
y = mx + b slope(m) = -2 (1,-1)...x = 1 and y = -1 now we sub and find b, the y int -1 = -2(1) + b -1 = -2 + b -1 + 2 = b 1 = b
It's already in a form that only ha positive exponents. Just to state it though you could rewrite it as or The question asks for positive exponents though so yu don't need to do that.
