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Novay_Z [31]
2 years ago
9

Given trapezoid KLMN with midsegment EF, where KL = 4 and MN = 7, what is the length of EF?​

Mathematics
1 answer:
TEA [102]2 years ago
3 0

Answer:

EF= 5.5

Step-by-step explanation:

7 + 4 = 11

11 divided by 2 = 5.5

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PLEAS HELP What is x worth in this sentence? 12x + 25 = 73.
bagirrra123 [75]

Answer:

x=4

Step-by-step explanation:

12x-48 12*(4)

12=0

x=4=0

Add  4  to both sides of the equation

So x=4

12*4+25

48+25

73

4 0
3 years ago
Please answer these questions quick thank you!
BabaBlast [244]

Answer:

3

Step-by-step explanation:

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2 years ago
The vertical component of a force of 100 pounds that makes an angle of 30° with the horizontal is 50 pounds. is this true or fal
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6 0
3 years ago
1. The Senior Class of Great Ridge High School and Ann Arbor High School are planning a trip to Six Flags Theme Park. Great Ridg
Zanzabum

Answer:

A)14v + 16b = 1152

10v + 13b = 925

B)Number of students in a van = 8

Number of students in each bus = 65

C) Elimination method was easier.

Step-by-step explanation:

Let v be the number of students in a van

Let b be number of students in a bus

A) We are told the first school can fill 14 vans and 16 buses with 1152 students

Thus;

14v + 16b = 1152 - - - - - (eq 1)

Also,we are told that the second school can fill 10 vans and 13 buses with 925 students.

Thus;

10v + 13b = 925 - - - - (eq 2)

B) To solve this we will use elimination method.

Multiply eq (1) by 5 and multiply eq (2) by 7 to give;

70v + 80b = 5760 - - - - eq(3)

70v + 91b = 6475 - - - - - eq(4)

Subtract eq(3) from eq(4) to give;

91b - 80b = 6475 - 5760

11b = 715

b = 715/11

b = 65

Put 65 for b in eq(3) to give;

70v + 80(65) = 5760

70v = 5760 - 80(65)

70v = 560

v = 560/70

v = 8

Number of students in a van = 8

Number of students in each bus = 65

C) Elimination method was used because in both equations, we had different digits attached and so it would have been more tedious to use substitution method or graphical method. Thus, elimination method was more easier.

7 0
3 years ago
A perfect square ends with the same two digits. How many possible values of this digit are there?
Alex73 [517]

Answer:

A perfect square is a whole number that is the square of another whole number.

n*n = N

where n and N are whole numbers.

Now, "a perfect square ends with the same two digits".

This can be really trivial.

For example, if we take the number 10, and we square it, we will have:

10*10 = 100

The last two digits of 100 are zeros, so it ends with the same two digits.

Now, if now we take:

100*100 = 10,000

10,000 is also a perfect square, and the two last digits are zeros again.

So we can see a pattern here, we can go forever with this:

1,000^2 = 1,000,000

10,000^2 = 100,000,000

etc...

So we can find infinite perfect squares that end with the same two digits.

7 0
3 years ago
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