Question

Can anyone help me with this one ?

Answer 1

Answer:

26

Step-by-step explanation:

First find the triangle of the base by using the Pythagorean theorem

$\sqrt{24^2+6^2} = \sqrt{576+36} = \sqrt{612}$

So the diagonal of the base is the square root of 612

Now we can find the hypotenuse of GP using that and 8 in the Pythagorean theorem.

$\sqrt{\sqrt{612}^2 + 8^2} = \sqrt{612+64} = \sqrt{676} = 26$

(Square root times itself is the number inside):

$\sqrt{64} * \sqrt{64} = 64\\\sqrt{22} * \sqrt{22} = 22$

GP = 26

Hope this helps :)