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Katarina [22]
3 years ago
6

The cost of a car rental is twenty-five dollars a day plus ten cents a mile. What is the total cost, in dollars, if the car is r

ented for three days and driven a total of six hundred and sixty miles? A) 86 B) 91 C) 97 D) 141
Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

The total cost is D) $141

Step-by-step explanation:

To solve we can use the equation: y=25d+0.10m

d= number of days  m= number of miles

We know both of these values so we can plug them in and solve.

y= 25(3) + 0.10(660)

y= 75 + 66

y = 141

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93.64m to metres and centimetres
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2 years ago
Help with the problem in picture ​
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2 years ago
Rachael is a nurse. She earns 12 vacation days after working 768 hours. How many hours does Rachael need to work to earn 1 vacat
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6 0
3 years ago
Read 2 more answers
PLEASE HELP!!! WILL REWARD!!
BabaBlast [244]
X+y+z=t
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3 0
3 years ago
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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
3 years ago
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