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2 years ago

Help!!! ill give brainliest!!

Mathematics

1 answer:

Komok [63]2 years ago

3 0

Answer:

4.123

Step-by-step explanation:

Just have to think what times itself = 17 and I thought well Istill close to 4 and then I just did the work

also PLZ MARK ME BRAINLIEST

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Please help meeeeeeee

strojnjashka [21]

Answer:

Volume of the cylinder = 602.88 square centimeters

Step-by-step explanation:

Given that:

Radius of cylinder = 4 cm

Height of cylinder = 12 cm

Volume of a cylinder is given by the following formula;

Volume = πr²h

Putting π = 3.14, r = 4 and h = 12 in the formula

Volume = 3.14 * (4)² * 12

Volume = 3.14 * 16 * 12

Volume = 602.88 square centimeters

Hence,

Volume of the cylinder = 602.88 square centimeters

5 0

2 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Need help asap i will help u if u help me

sammy [17]

Answer: (10,9) is the correct answer.

4 0

3 years ago

Read 2 more answers

Mia currently has 10 email subscribers to her blog and gains an average of 10 new subscribers per day. Julie currently has 100 e

user100 [1]

Answer:

Equations:

Mia: 10 + 10x = y

Julie: 100 - 5x = y

Solved: (6, 70)

Step-by-step explanation:

Mia: 10 + 10x = y

She already has 10 (10) and gains 10 (+10) per day (x). Total is y gained.

Julie: 100 - 5x = y

She already has 100 (100) and loses 5 (-5) per day (x). Total is y gained.

Then I simply solve

10 + 10x = y

100 - 5x = y

Resulting in (6, 70)

6 0

2 years ago

The volumes of two bodies are measured to be

valentinak56 [21]

Answer:

Sum of volumes = (16.6 ± 0.03) cm³

Difference of volumes = (3.8 ± 0.03) cm³

Step-by-step explanation:

Solution

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Hence, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

5 0

2 years ago

Read 2 more answers