There are 50 different possible debating teams that could be selected as obtained using COMBINATION.
Since there are EQUAL number of juniors and seniors ;
Then we have 5 of each.
Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION
since the team MUST contain 4 SENIORS and 2 JUNIORS
4 Seniors from 5 = 5C4 = 5
2 Juniors from 5 = 5C2 = 10
Hence, (5C4 * 5C2) = 5 * 10 = 50
Hence, there are 50 different possible debating teams that could be selected.
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brainly.com/question/8018593
Answer:
-5
Step-by-step explanation:
Answer:
80 units²
Step-by-step explanation:
Given <u>vertices</u> of a rectangle:
- A = (-8, 5)
- B = (2, 5)
- C = (2, -3)
- D = (-8, -3)
As points A and D share the <u>same x-coordinate</u>, and points B and C share the <u>same x-coordinate</u>, the difference between the different <u>x-coordinates</u> is the length of the rectangle:
As points A and B share the <u>same y-coordinate</u>, and points C and D share the <u>same y-coordinate</u>, the difference between the different <u>y-coordinates</u> is the width of the rectangle:
Therefore:
Answer:
90+0=90
Step-by-step explanation:
hope it helpsss
heheh
Answer:
you should try adding then subtractung the total to the part