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2 years ago

Does that look right

Mathematics

2 answers:

Tju [1.3M]2 years ago

7 0

looks right to me! :)

Vlad [161]2 years ago

4 0

Yup! looks correct!! hope you have a nice day/night

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Learn with<br> Add.<br> (2h + 8) + (9h + 4)<br> Submit

ahrayia [7]

Answer:

11h+12

Step-by-step explanation:

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2 years ago

Section 5.2 Problem 17:

Elina [12.6K]

This DE has characteristic equation

$4r^2 - 12r + 9r = (2r - 3)^2 = 0$

with a repeated root at r = 3/2. Then the characteristic solution is

$y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}$

which has derivative

${y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}$

Use the given initial conditions to solve for the constants:

$y(0) = 3 \implies 3 = C_1$

$y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2$

and so the particular solution to the IVP is

$\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}$

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2 years ago

Bernice found that the slope of a trend line is –3 and a point on the trend line is (8, 10). She wanted to find the equation of

shusha [124]

Answer:b

Step-by-step explanation:

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3 years ago

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

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For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

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3 years ago

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jeyben [28]

The average is $41.30

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3 years ago