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2 years ago

HELPPPPP!!!!!!

Mathematics

1 answer:

Advocard [28]2 years ago

3 0

Answer:

KE=112 $\frac{kg * m^{2} }{s^{2} }$

Step-by-step explanation:

Kinetic Energy (KE) = (1/2)*mass*v^2

KE=(1/2)*.14*40^2

KE=112 $\frac{kg * m^{2} }{s^{2} }$

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Please help and hurry please

kakasveta [241]

Answer:

x=7.48

Step-by-step explanation:

13^2+x^2=15^2

169+x^2=225

x^2=56

x=7.48

6 0

2 years ago

Read 2 more answers

5x+20y=4 x=-4y+1 Solve for x/y

Andrews [41]

Hi there!

Looks like a lot of work is going on here.

Let's start by solving this equation for the x.

$5x + 20y = 4$

Step 1) Add -20y to both sides.

$5x + 20y + - 20y = 4 - 20y 5x = -20y + 4$

Step 2) Divide both sides by 5.

$\frac{5x}{5} = \frac{-20y + 4}{5}$

$x = -4y + \frac{4}{5}$

Final Answer:

$x = -4y + \frac{4}{5}$

Now, let's solve for y.

Step 1) Add -5x to both sides.

$5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4$

Step 2) Divide both sides by 20.

$\frac{20y}{20} = \frac{-5x + 4}{20}$

$y = \frac{-1}{4} x + \frac{1}{5}$

Final Answer:

$y = \frac{-1}{4} x + \frac{1}{5}$

Hope this helps! :D

Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

6 0

3 years ago

The length of a rectangle is 6 ft longer than its width. if the perimeter of the rectangle is 52 ft , find its area.

sveticcg [70]

Let its width be w and length= w+6
2(w+6+w)=52
4w+12=52
4w=40
w=10
Area=10*(10+6)=160

7 0

3 years ago

A box of 10 bars of soap costs $10.88, while the same brand with 4 more bars costs $17.62. Which is the better buy? Round your a

horsena [70]

The box of 10 is a better buy because each bar of soap is worth $1.08 instead of $1.26 that you would pay for the box of 14.

7 0

3 years ago

What is the nth term?

kumpel [21]

Let $a_k$ denote the kth term of the sequence. Then

$a_k=a_1+d(k-1)$

where d is the common difference between consecutive terms in the sequence and a₁ is the first term.

The sum of the first n terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the nth term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago