Answer:
Let d = the one-way trip
Write a time equation: time = dist/speed
time out + time back = 4.5 hrs
d/80 + d/100 = 4.5
Multiply by 400 to clear the denominators
400*d/80 + 400*d/100 = 400(4.5)
Cancel the denominators
5d + 4d = 1800
d = 1800/9
d = 200 miles max distance
Given:
Desmond deposits $ 50 monthly.
Yearly he deposits = $50×12 = $ 600
Rate of interest compounded monthly = 4.7%
To find the amount he will receive after 10 years and the rate of change the value of his account after 10 years.
Formula
where,
A be the final amount
P be the principal
r be the rate of interest
t be the time and
n be the number of times the interest is compounded.
Now,
Taking,
P = 600, r = 4.7, n = 12, t = 10 we get,
or,
or,
Now,
At starting he has $ 600
At the end of 10 years he will be having $ 959.1
So,
The amount of change in his account = $ (959.1-600) = $ 359.1
Therefore the rate of change =
= 59.85%
Hence,
a) His account will contain $ 959.1 after 10 years.
b) The rate of change in his account is 59.85% after 10 years.
Answer:
A.
Step-by-step explanation:
x2 - 3x - 10. = 0
x2 + 2x - 5x - 10 = 0
(x2 + 2x) (-5x - 10) = 0
x (x + 2) - 5 (x + 2) = 0
(x - 5) (x + 2) = 0
x - 5 = 0 x + 2 = 0
x = 5 or x = - 2.