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telo118 [61]
3 years ago
12

A test of H0: p = 0.5 versus Ha: p > 0.5 has the test statistic z = 1.15. Part A: What conclusion can you draw at the 5% sign

ificance level? At the 1% significance level? (6 points) Part B: If the alternative hypothesis is Ha: p ≠ 0.5, what conclusion can you draw at the 5% significance level? At the 1% significance level? (4 points)

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

Part A: The null hypothesis failed to be rejected.

Part B: The null hypothesis failed to be rejected.

Step-by-step explanation:

We have an hypothesis test with null and alternative hypothesis H0: p = 0.5 versus Ha: p > 0.5, which has the test statistic z=1.15.

Part A: If the significance level is 0.05, the conclusion depends on the P-value.

If the P-value is below 5%, the null hypothesis is rejected.

The P-value for this right-tailed tes and z=1.15 is:

P-value=P(z>1.15)=0.125

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

Part B: In this case, the significance level is 0.01 and, as the alternative hypothesis is defined with an unequal sign, the test is two-tailed.

This changes the way we calculate the P-value, as we need to compute the two tails.

The P-value is:

P-value=2P(z>1.15)=0.25

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

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Answer:

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100%-> 450

15%-> 67.50

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3 years ago
Divide using long division. HELP ASAP!!
pav-90 [236]

Answer:

The answer to your question is the first option

Step-by-step explanation:

Write the division

                               7x³  - 7x²   + 6x   +4                        Result

                  x + 1     7x⁴  -  0x³  - 1x²  +  10x  + 15

                             -7x⁴   -  7x³

                               0     -  7x³  - 1x²      

                                       + 7x³ +7x²

                                          0    + 6x² +  10x

                                                - 6x²  -    6x

                                                    0    +   4x  + 15

                                                          -    4x  -   4

                                                                0   + 11            Remainder

Result =  7x³ - 7x² + 6x + 4 + 11 / x + 1

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Solution:

we are given that

If G is the midpoint of FH,  it mean that

FG=GH

we are also given that

FG=11x-7 ,GH= 3x+9

So we can write

11x-7=3x+9\\&#10;\\&#10;11x-3x=7+9\\&#10;\\&#10;8x=16\\&#10;\\&#10;x=2

So FG=11x-7=11*\frac{1}{2}-7=11*2-7=15


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3 0
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