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telo118 [61]
3 years ago
12

A test of H0: p = 0.5 versus Ha: p > 0.5 has the test statistic z = 1.15. Part A: What conclusion can you draw at the 5% sign

ificance level? At the 1% significance level? (6 points) Part B: If the alternative hypothesis is Ha: p ≠ 0.5, what conclusion can you draw at the 5% significance level? At the 1% significance level? (4 points)

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

Part A: The null hypothesis failed to be rejected.

Part B: The null hypothesis failed to be rejected.

Step-by-step explanation:

We have an hypothesis test with null and alternative hypothesis H0: p = 0.5 versus Ha: p > 0.5, which has the test statistic z=1.15.

Part A: If the significance level is 0.05, the conclusion depends on the P-value.

If the P-value is below 5%, the null hypothesis is rejected.

The P-value for this right-tailed tes and z=1.15 is:

P-value=P(z>1.15)=0.125

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

Part B: In this case, the significance level is 0.01 and, as the alternative hypothesis is defined with an unequal sign, the test is two-tailed.

This changes the way we calculate the P-value, as we need to compute the two tails.

The P-value is:

P-value=2P(z>1.15)=0.25

The P-value is bigger than the significance level, so the effect is not significant and the null hypothesis is failed to be rejected.

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Which function has a range of y&lt;3?<br> y=3(2)<br> y=2(3)*<br> y=-(2)* + 3<br> y= (2)X-3
Bingel [31]

The function that has a range of y<3 is y=-(2)* + 3

Answer: Option(c)

<u>Step-by-step explanation:</u>

Solution:

Lets shall evaluate the options given in the question

In Option 1; y=3(2) that is

y=3 \times 2=6

So the value of y>3 and thus option 1 fails

In option 2; y=2(3)*

This expression indicates that the power of 3 all result in positive values and sometimes zero such that for 2 \times 3^{0}=0 and for values other than one y will be greater than 3. so option 2 fails.

In option 4; y=2x(-3)

On solving we get y=2 \times(-3)=-6

Though it is less than 3 but it has an negative value. So option 4 fails.

In option 3; y=-(2)* + 3

This option indicates for all power values of -2 the y value will be less than 3 such that

For power value 0 we get

y=-2^{0}+3

y=0+3=3

And for the power value 1 we get

y=-2^{1}+3

y=-2+3=1

So in the both the occasion the value of y<3 than and it is not an negative value and thus option 3 satisfy the functional range y<3.

Result:

Thus the function that has a range of y<3 is y=-(2)* + 3

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3 years ago
What is the equation of the circle if the center is (-4,10) and radius of 7
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Solve the equation below for x by graphing. x ≈ -2.50 x ≈ 2.50 x ≈ -0.50 x ≈ -6.00
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13....................
Mashcka [7]

13.

(a)

y=-5x^2+21x-3

for x = 2:

y=-5(2)^2+21(2)-3=-20+42-3=19

for x = 5

y=-5(5)^2+21(5)-3=-125+105-3=-23

(b)

The graph is:

(c)

Using the graph:

\begin{gathered} x=1.8,y=18.6 \\ x=0.548,y=7 \\ x=3.65,y=7 \end{gathered}\begin{gathered} x=1.8 \\ y=-5(1.8)^2+21(1.8)-3=-16.2+37.8-3=18.6 \end{gathered}\begin{gathered} y=7 \\ -5x^2+21x-3=7 \\ -5x^2+21x-10=0 \end{gathered}

Using the quadratic formula:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}

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