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4 years ago

The color that we see when looking at a pigmented object is ______.

Physics

1 answer:

guajiro [1.7K]4 years ago

7 0

D. the wavelengths that the pigmented object after interacting with sunlight

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A. It decreases gradually. B. It increases gradually. C. It falls sharply. D. It remains the same.

harina [27]

Answer:

It remains the same.

Explanation:

» At 100°C, it is the boiling point of water. And it starts changing from liquid state to gaseous state

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3 0

2 years ago

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An iron nail goes through a chemical change when iron in the nail combines with oxygen in the air to form iron oxide. This compo

Mazyrski [523]

It is like that, except most nails are steel or stainless steel, slowing to rusting process to about 5 years.

6 0

3 years ago

Which group of stars is represented by the line image

Lerok [7]

Answer:

ursa Major

Explanation:

8 0

3 years ago

Read 2 more answers

A 160 pF capacitor and a 640 pF capacitor are both charged to 1.8 kV. They are then disconnected from the voltage source and are

Tems11 [23]

Answer:

a). The resulting potential difference across each capacitor is 1.8 kV.

(b). The energy lost is zero.

Explanation:

Given that,

First capacitor = 160 pF

Second capacitor = 640 pF

Voltage = 1.8 kV

(a). We need to calculate the initial charge

Using formula of charge

$q=CV$

Put the value into the formula

$q=160\times10^{-12}\times1.8\times10^{3}$

$q=2.88\times10^{-7}\ C$

$q=288\ nC$

We need to calculate the final charge

Using formula of charge

$q=CV$

$q=640\times10^{-12}\times1.8\times10^{3}$

$q=1152\ nC$

The total charge is

$Q=288+1152$

$Q=1440\ nC$

We need to calculate the resulting potential difference across each capacitor

Using formula of potential difference

$V=\dfrac{Q}{C_{1}+C_{2}}}$

Put the value into the formula

$V=\dfrac{1440\times10^{-9}}{(160+640)\times10^{-12}}$

$V=1.8\ kV$

(b). We need to calculate the energy lost when the connections are made

Using formula of energy

$E=\dfrac{1}{2}CV^2-\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times(160+640)\times10^{-12}\times1800^2-\dfrac{1}{2}\times(160+640)\times10^{-12}\times1800^2$

$E=0$

Hence, (a). The resulting potential difference across each capacitor is 1.8 kV.

(b). The energy lost is zero.

5 0

3 years ago

A helium filled balloon has a volume of 4.5 m^3. What mass of helium does it hold if the density of helium is 1.8 x 10^-4 g/cm^3

maria [59]

Answer:

mass of the helium gas will be $=8.1\times 10^{-7}kg$

Explanation:

We have given volume of the helium $V=4.5m^3$

Density of helium gas $d=1.8\times 10^{-4}cm^3=1.8\times 10^{-10}m^3$

We have find the mass of the helium gas

We know that mass is given by mass = volume×density

So mass = $4.5\times 1.8\times 10^{-10}=8.1\times 10^{-10}gram=8.1\times 10^{-7}kg$

So mass of the helium gas will be $=8.1\times 10^{-7}kg$

5 0

3 years ago