Question

18. Two objects, X and Y. accelerate from rest with the same constant acceleration. Object X accelerates for

Answer 1

Answer:

e. Object X has traveled four times as far as object Y.

Explanation:

The distance covered by an object in uniform accelerated motion is given by:

$d=ut+\frac{1}{2}at^2$

where

u is the initial velocity

t is the time

a is the acceleration

The two objects in the problem have same initial velocity, u = 0 (since they start from rest), so we can rewrite the equation as

$d=\frac{1}{2}at^2$

We see that the distance covered is proportional to the square of the time. In this problem, the two objects X and Y have same acceleration, but object X accelerates for twice the time: since $d \propto t^2$, this means that the distance covered by X will be $2^2 = 4$ times higher that the distance covered by object Y.