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Tems11 [23]
3 years ago
6

You wind a small paper tube uniformly with 153 turns of thin wire to form a solenoid. The tube\'s diameter is 5.11 mm and its le

ngth is 2.47 cm. What is the inductance, in microhenries, of your solenoid
Physics
1 answer:
lina2011 [118]3 years ago
3 0

The concept required to solve this problem is linked to inductance. This can be defined as the product between the permeability in free space by the number of turns squared by the area over the length. Recall that Inductance is defined as the opposition of a conductive element to changes in the current flowing through it. Mathematically it can be described as

L = \frac{\mu N^2 A}{l}

Here,

\mu = Permeability at free space

N = Number of loops

A = Cross-sectional Area

l = Length

Replacing with our values we have,

L = \frac{(4\pi *10^{-7})(153)^2(\pi (\frac{5.11*10^{-3}}{2})^2)}{2.47*10^{-2}}

L = 0.00002442H

L = 24.42\mu H

Therefore the Inductance is 24.42\mu H

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3 years ago
7.For the following questions, use a periodic table and your atomic calculations to find the unknown information about each isot
Oksana_A [137]
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Applying newton's version of kepler's third law (or the orbital velocity law) to the a star orbiting 40,000 light-years from the
Ugo [173]

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<h3></h3><h3>What is orbital velocity law?</h3>

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5 0
1 year ago
I will give Brainliest to whoever can answer!!!!
Alexus [3.1K]

Answer:

The nodes and anti nodes would reverse roles.

Explanation:

I believe it has to do with the path differences. If waves are in phase, then the path differences are such that the waves reach the screen with crests superimposing crests and troughs superimposing troughs. This happens when the periods of each wave are equal or the paths themselves differ by a whole number multiple of the wavelength (λ, 2λ, 3λ, ...).

Now make these waves out of phase. Then half of the waves will travel half a wavelength farther than the rest. So the path difference will be 0.5λ, 1.5λ, 2.5λ, ....

4 0
3 years ago
A rocket has a mass 280(103) slugs on earth. Specify its mass in SI units, and its weight in SI units.
saw5 [17]

To solve this problem we will apply the concepts related to the conversion of units for which we will have that 1 slug is equal to 14.59kg. At the same time we will use Newton's second law for which weight is defined as the product between mass and acceleration (Due to gravity). This is then

A: Using the conversion ratio of slug to kilogram we have to,

1 slug = 14.59kg

Then

m = 280*10^3 slugs (\frac{14.59kg}{1slug})

m = 4.09*10^6kg

B: Using Newton's second law we have to,

W = mg

W = (4.09*10^6)(9.8)

W = 40034960N\approx 4*10^7N

8 0
3 years ago
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