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Kaylis [27]
3 years ago
15

What is the normal force and gravitational force on a 55 kg person standing stationary?

Physics
1 answer:
Alex777 [14]3 years ago
4 0

Answer:

539.55 N for both

Explanation:

F=ma

Mass is given at 55kg

And when finding gravitational force gravity's constant is an acceleration of 9.81m/s

F=(55)(9.81)

F= 539.55 N (for both)

Normal force cancels out gravitational force that's why we don't fall throught the floor.

We push down on the floor due to gravitational force but normal force keeps us upright pushing an equal amount back.

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A 0.16 kg billiard ball moving at 1.20 m/s collides elastically with one of the same mass at rest. It continues at a speed of 0.
Rainbow [258]
Use energy conservation to calculate the speed!
Total kinetic energy before collision = total kinetic energy after the collision.
5 0
3 years ago
PlS help <br>I really need help.<br>very urgent<br><br>PLS help
horsena [70]
Draw a freebody diagram, it will explain it really well

the boat is floating on top of the water, which means that the net acceleration in the y direction must be zero

the boat is not sinking (dominant downwards acceleration/force)
the boat is not flying (dominant upward acceleration/force)

that measn
F_{net_y} =0

now, if you drew the FBD, you only have 2 forces acting on the boat.
the upward bouyancy force on the boat and the downward force due to weight

F_{net_y}= F_{bouyancy} - F_{weight}

since the net force is equal to zero

F_{bouyancy} - F_{weight} = 0

and thus

F_{bouyancy} = F_{weight}
4 0
3 years ago
Question 1 (1 point)
IrinaK [193]
  1.  momentum  
  2. Yes, if the elephant is standing still.
  3. Fullback  
  4. impulse acting on it.  
  5. 2.25 N∙s
  6. A cannon firing.
  7. Inelastic  
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8 0
3 years ago
What is the electrical force between q1 and q2? Recall that k = 8.99 × 109 N•meters squared over Coulombs squared.. 4.3 × 10 N 3
Rudiy27

Answer:

Explanation:

Incomplete question but for understanding.

We want to find the electrical force between two charges, then you can use the coulombs law which states that the force of attraction or repulsion between two charges is directly proportional to the product of the two charges and inversely proportional to the square of their distance apart,

So,

F = kq1•q2 / r²

Where k is a constant and it is given as

K = 8.99 × 10^9 Nm²/C²

q1 and q2 are the charges and in this question it is not given, so the question is incomplete. Let assume that,

q1 = - 1.609 × 10^-19 C electron

q2 = 1.609 × 10^-19 C proton

Since unlike charges attract, then it is force of attraction

Also, r is the distance apart and it is not given, let assume the distance between the two charges is 2 × 10^-5m

Then,

F = kq1•q2 / r²

F = 8.99 × 10^9 × 1.609 × 10^-19 × 1.609 × 10^-19 / (2 × 10^-5)²

F = 5.82 × 10^-19 N

7 0
4 years ago
Read 2 more answers
How do you determine the acceleration of an object?
Gelneren [198K]

Are you familiar with any basic calculus? If so, we can just look at this derivative and see what's happening with our units here..

a = \frac{dv}{dt}

Here it shows that acceleration is the derivative of velocity with respect to time. In other words, we can say that:

a=\frac{\Delta v}{\Delta t}

We can read that equation as: "acceleration is the change of velocity divided by the change in time (aka the time interval)."

If you're not familiar with calculus, we can use a simple equation of motion:

v_f = v_i+at

where:

vf = final velocity

vi = initial velocity

a = acceleration

t = observed time interval

We can rearrange this equation to find:

a = \frac{v_f - v_i}{t}

This is the same exact thing we wrote before!

8 0
3 years ago
Read 2 more answers
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