Answer:
C. 8
Step-by-step explanation:
Sorry guys the highness of the % is 93 points so here you go thx for helping!!:}
1 answer:
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Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t
v(t) can be obtained by integrating a(t)
v(t) =
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
<h3>Answer : 60°</h3><h3>Way to do </h3>
#look pic for detailed info
180° - 125° = 55°
180° - 115° = 65°
180° - 55° - 65° = 60°
180° - 60° = 120°
180° - 120° = 60°